Online Algebraic Equation Solver

Solve linear, quadratic, polynomial, and systems of equations with detailed steps. Finds both real and complex roots with discriminant analysis.

Quadratic Equation (ax² + bx + c = 0)

a
x² +
b
x +
c
= 0
Examples:
Roots of Equation
x₁ = 3, x₂ = 2
Two distinct real roots (D > 0)
Discriminant (D)1
Parabola Vertex(2.5, -0.25)
Factored form(x − 3)(x − 2) = 0
Step-by-step solution
1.x² - 5x + 6 = 0
2.D = b² − 4ac = (-5)² − 4 × (1) × (6) = 25 − 24 = 1
3.√D = √1 ≈ 1
4.x₁ = (−b + √D) / 2a = (−(-5) + 1) / 2 = 3
5.x₂ = (−b − √D) / 2a = (−(-5) − 1) / 2 = 2

How to use

  1. Type or paste mathematical equation (e.g. 2x + 5 = 15 or x² - 5x + 6 = 0).
  2. Specify unknown variable (default x).
  3. Click calculate.
  4. View computed real/complex roots and step-by-step algebraic deduction.

Equation Solution Examples

Linear equation: 2x - 8 = 0 → x = 4.

Quadratic equation: x² - 5x + 6 = 0 → D = 25 - 24 = 1, roots x1 = 2, x2 = 3.

No real roots: x² + 4 = 0 → complex conjugate roots x = ±2i.

Calculation Methodology

For quadratic ax² + bx + c = 0, discriminant D = b² - 4ac dictates solutions: D > 0 yields two distinct real roots; D = 0 gives a single repeated root; D < 0 yields complex conjugate pairs.

Frequently Asked Questions

What equation classes can be solved?

Linear, quadratic, biquadratic, cubic polynomial equations, and linear systems.

What does the discriminant D indicate?

The expression D = b² - 4ac determines the quantity and nature of roots for a quadratic polynomial.

What happens when discriminant D is negative?

The equation has no real number roots, resulting instead in two complex conjugate roots involving imaginary unit i.

How to enter powers and multipliers?

Use caret ^ for powers (x^2) and asterisk * for multiplication.

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