Online Thermodynamics & Heat Quantity Calculator

Compute heat energy Q transferred during temperature changes. Useful for physics students, heating engineers, and thermal design calculations.

Heat Energy (Q)
334.88 кДж
Heating (heat absorbed)80.0382 ккал
Formula:Q = c · m · |ΔT| = 4186 Дж/(кг·К) × 1 кг × 80 °C
Joules (J)334,880
Megajoules (MJ)0.3349
Watt-hours (Wh)93.02
Kilowatt-hours (kWh)0.093

How to use

  1. Input substance mass m in kg.
  2. Specify specific heat capacity c (J/(kg·°C)) or choose substance.
  3. Input initial temperature t1 and target temperature t2.
  4. View resulting thermal heat energy Q in Joules, kJ, or kWh.

Calculation Example

Heating 10 liters (10 kg) of water from 20 °C to 80 °C (c = 4200 J/(kg·°C)):

Temperature delta: ΔT = 80 - 20 = 60 °C.

Heat quantity: Q = c * m * ΔT = 4200 * 10 * 60 = 2,520,000 J (2.52 MJ or ≈ 0.70 kWh).

Calculation Methodology

Sensible heat exchange formula without phase change: Q = c * m * ΔT, where c is specific heat, m is mass, and ΔT is temperature change.

Frequently Asked Questions

What is specific heat capacity?

The amount of heat required to raise the temperature of 1 kilogram of a substance by 1 degree Celsius.

What units measure thermal heat energy?

Joules (J), kilojoules (kJ), calories (cal), or kilowatt-hours (kWh).

What does a negative Q indicate?

A negative value indicates heat release and cooling to the environment.

What is the specific heat capacity of liquid water?

Water has a high specific heat capacity of approximately 4184–4200 J/(kg·°C).

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